To measure the area of the irregular rectangle with the given dimensions (in feet and inches) using the average rule, we need to convert all the measurements to the same unit. Let's convert the 10 inches to feet first.
1 inch is equal to 1/12 feet. Therefore, 10 inches is equal to 10/12 = 5/6 feet.
Now, we have the following dimensions:
Side A: 60 feet
Side B: 60 feet 5/6 feet
Side C: 50 feet
Side D: 45 feet
To proceed with the calculations, we can convert the mixed measurement for Side B to decimal feet:
Side B = 60 feet + 5/6 feet = 60.8333 feet (approximating to four decimal places).
Now, we can use these dimensions to calculate the area:
1. Divide the irregular rectangle into smaller rectangles:
- Rectangle 1: A x B (60 feet x 60.8333 feet)
- Rectangle 2: C x D (50 feet x 45 feet)
2. Calculate the area of each rectangle:
- Area of Rectangle 1 = 60 feet x 60.8333 feet ≈ 3649.998 square feet
- Area of Rectangle 2 = 50 feet x 45 feet = 2250 square feet
3. Find the average area:
- Average area = (Area of Rectangle 1 + Area of Rectangle 2) / 2
- Average area = (3649.998 square feet + 2250 square feet) / 2
- Average area ≈ 5899.99 square feet / 2
- Average area ≈ 2949.995 square feet
Therefore, the average area of the irregular rectangle is approximately 2949.995 square feet.